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Gay Lussac's Law, Avagadro's Law

What is the m...

Question

What is the mass of $6.022 \times 10^{23}$ molecules of ${N H}_{3}$ ?

A

45.06 g

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B

19.06 g

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C

17.04 g

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D

31.02 g

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Solution

The correct option is B $17.04 g$
$1 m o l e$ of $N H_{3}$ has $6.023 \times 10^{23}$ molecules of $N H_{3}$ .
So, the mass of $6.023 \times 10^{23}$ molecules of $N H_{3}$ . is the mass of $1 m o l e$ of $N H_{3}$ i.e. molar mass of $N H_{3} .$
Molar mass $= 14.01 + 3 (1.01) = 17.04 g$

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