What is the mass of 6-022- 10 23 molecules of NH3-

The correct option is B 17.04g 1 mole of NH_3 has 6.023 × 10^23 molecules of #160; NH_3 .So, the mass of #160; 6.023 × 10^23 ...

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Standard XII

Chemistry

Gay Lussac's Law, Avagadro's Law

What is the m...

Question

What is the mass of $6.022 \times 10^{23}$ molecules of ${N H}_{3}$ ?

45.06 g

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19.06 g

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17.04 g

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31.02 g

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Solution

The correct option is B $17.04 g$
$1 m o l e$ of $N H_{3}$ has $6.023 \times 10^{23}$ molecules of $N H_{3}$ .
So, the mass of $6.023 \times 10^{23}$ molecules of $N H_{3}$ . is the mass of $1 m o l e$ of $N H_{3}$ i.e. molar mass of $N H_{3} .$
Molar mass $= 14.01 + 3 (1.01) = 17.04 g$

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Similar questions

Q. 12 g C-12 contains

6.022 \times 10^{23}

atoms of carbon.
(a)

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of carbon atoms present in 48 g C-12.
(c) Which weighs more,

6.022 \times 10^{23}

molecules of

C O_{2}

6.022 \times 10^{23}

molecules of

H_{2} O

Q. Calculate the mass of the following.

6.022 \times 10^{23}

number of

N_{2}

molecules.

Q. Data about three gases at STP is given:
(A)

16 g C H_{4}

(B)

11.2 L C O_{2}

(C)

6.022 \times 10^{23}

molecules of

N H_{3}

(a) The number

6.022 \times 10^{23}

is known as .............
(b) Calculate the number of

C H_{4}

molecules present in 16 g

C H_{4}

.
(c) Arrange

A, B

and

C

in the increasing order of their mass in grams.
[given: At mass:

H = 1, C = 12, N = 14, O = 16

]

The mass of 6.022 × 10²³ number of N₂ molecules is:

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

(a) $12.044 \times 10^{20}$ molecules (b) $6.022 \times 10^{23}$ molecules

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What is the mass of 6.022×1023 molecules of NH3?

The correct option is B 17.04g1 mole of NH3 has 6.023×1023 molecules of NH3.So, the mass of 6.023×1023 molecules of NH3. is the mass of 1 mole of NH3 i.e. molar mass of NH3.Molar mass =14.01+3(1.01)=17.04 g

What is the mass of $6.022 \times 10^{23}$ molecules of ${N H}_{3}$ ?

The correct option is B $17.04 g$
$1 m o l e$ of $N H_{3}$ has $6.023 \times 10^{23}$ molecules of $N H_{3}$ .
So, the mass of $6.023 \times 10^{23}$ molecules of $N H_{3}$ . is the mass of $1 m o l e$ of $N H_{3}$ i.e. molar mass of $N H_{3} .$
Molar mass $= 14.01 + 3 (1.01) = 17.04 g$