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Stoichiometric Calculations

What is the m...

Question

What is the mass of glucose required to produce 44g of CO₂

on complete combustion?

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Solution

mole= mass / molar mass (molar mass CO2- 12+16x2=44)

=44/ 44
= 1 mole
our ratio was 1 mole of glucose to 6 moles of CO2
that means the moles of glucose required for this reaction is 1/6 moles

Therefore calculate the mass of Glucose;

mass of a compound= moles x its molar mass

molar mass of glucose, C6H12O6 =(12x6)+(1x12)+(16x6)
=72+12+96 = 190
hence mass = 190 x 1/6 = 31.667g

Therefore mass of glucose required is 31.667 grams

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