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Question

What is the mass of precipitate formed when 50 mL of 16.9% solution of AgNO3 is mixed with 50 mL of 5.8% NaCl solution ?

(Ag = 107.8, N = 14, O = 16, Na = 23, Cl = 35.5)


A
18g
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B
28g
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C
7g
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D
3.5g
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Solution

The correct option is B 7g
Moles of AgNO3=50×16.9100×169.8=0.05 moles
Moles of NaCl=50×5.8100×58.5=0.05 moles
AgNo3+NaClAgCl+NaNO3
Mass of AgCl = mole x molar mass
=0.05×143.5=7.16 g

Hence option C is correct.

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