Question

What is the mass of sulphur in combination with 5 g of iron in ferrous sulphide $\left(FeS\right)$.

• A. 3.2 gm
• B. 2.3 gm
• C. 2.9 gm
• D. 1.9 gm

Answer 1

The correct option is B

2.3 gm

According to law of constant proportionality:
During reaction 56 g of iron combines with 32 g of sulphur to form ferrous sulphide.
Given 5 grams of iron will combine with X grams of sulphur to form $FeS$
$X=\frac{5\times 32}{56}$
=2.85 g