Question

What is the mass of sulphur that would react with 5 g of iron to form ferrous sulphide $\text{(FeS)}$?

• A. 2.8

Answer 1

The correct option is A 2.8
The reaction that takes place in the given process is:

$\text{Fe + S}\to \text{FeS}$

$\bullet$ In the formation of FeS, the mass ratio of iron to sulphur is 56 : 32, which means 56 g of iron combines with 32 g of sulphur to form ferrous sulphide.

(Gram atomic mass of iron = 56 g, Gram atomic mass of sulphur = 32 g)

$\bullet$ Accordingly, 5 grams of iron will combine with 5×3256 g = 2.85 g of sulphur.

$\bullet$ So, 2.85 g of sulphur would react with 5 g of iron to form FeS.