What is the mass of sulphur that would react with 5 g of iron to form ferrous sulphide (FeS)?

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Solution

Fe + S → FeS

56 grams of iron reacts with 32 grams of sulphur.

So, 5 grams of iron reacts with ‘x’ grams of sulphur.

$\frac{56}{32} \times \frac{5}{x}$

x = 2.85 grams of sulphur

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What is the mass of sulphur that would react with 5 g of iron to form ferrous sulphide (FeS)?

Fe + S → FeS 56 grams of iron reacts with 32 grams of sulphur. So, 5 grams of iron reacts with ‘x’ grams of sulphur. 5632×5x x = 2.85 grams of sulphur

Fe + S → FeS

56 grams of iron reacts with 32 grams of sulphur.

So, 5 grams of iron reacts with ‘x’ grams of sulphur.

$\frac{56}{32} \times \frac{5}{x}$

x = 2.85 grams of sulphur