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Question

What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO3 is mixed with 50mL of 5.8% w/v NaCl solution?


[Ag=107.8,N=14,O=16,Na=23,Cl=35.5]


A
7 g
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B
14 g
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C
28 g
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D
3.5 g
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Solution

The correct option is A 7 g
The molar masses ofAgNO3,NaCl and AgCl are 169.8 g/mol, 58.5 g/mol and 143.3 g/mol respectively.

The number of moles of AgNO3 present is

50×16.9100×169.8=0.0497

The number of moles of NaCl present is

50×5.8100×58.5=0.0496

Thus, both AgNO3 and NaCl are present in the stoichiometric quantity.

The number of moles of AgCl formed is 0.0496.

The mass of AgCl formed is 0.0496×143.3=7 g.

Hence, the correct option is A

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