What is the mass percentage of carbon tetrachloride if $22 g$ of benzene is dissolved in $122 g$ of carbon tetrachloride?

84.72

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15.28

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50

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44

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Solution

The correct option is A $84.72$ %
Given:-
Mass of $C_{6} H_{6} = 22 g$

Mass of carbon tetrachloride $C C l_{4} = 122 g$

Formula:-

Mass % of benzene $= \frac{M a s s o f s o l u t e}{T o t a l m a s s o f s o l u t i o n} \times 100$

Mass of solute $= \frac{22}{22 + 122} \times 100 = 15.28 %$

Mass percentage of $C C l_{4} = 100 -$ mass % of $C_{6} H_{6}$

$= 100 - 15.28 = 84.72 %$

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Similar questions

(C_{6} H_{6})

(C C l_{4})

22 g

122 g

30 %

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