What is the maximum current that can be drawn from a cell of emf E and internal resistance r connected to an external resistance R?

infinite

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I = E/R

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I = E/(R+r)

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I = E/r

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Solution

The correct option is D
I = E/r

as the maximum current that can be drawn from a cell is for R =0 and it is I = E/r.

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(E, r), (\frac{E}{n}, \frac{r}{n}), (\frac{E}{n^{2}}, \frac{r}{n^{2}}), (\frac{E}{n^{3}}, \frac{r}{n^{3}}), . . . .

\frac{n r}{n - 1}

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