What is the maximum height achieved when a projectile is thrown with a velocity $v_{o}$ at an angle $θ$ from the horizontal?

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Solution

Maximum height reached, $H = \frac{v_{0}^{2} s i n^{2} θ}{2 g}$

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What is the maximum height achieved when a projectile is thrown with a velocity vo at an angle θ from the horizontal?

Maximum height reached, H=v20sin2θ2g

What is the maximum height achieved when a projectile is thrown with a velocity $v_{o}$ at an angle $θ$ from the horizontal?

Maximum height reached, $H = \frac{v_{0}^{2} s i n^{2} θ}{2 g}$