What is the maximum length of a pencil that can be placed in a rectangular box of dimensions (8 cm × 6 cm × 5 cm)?
(a) 8 cm
(b) 9.5 cm
(c) 19 cm
(d) 11.2 cm

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Solution

(d) 11.2 cm
Maximum length of the pencil = diagonal of the box
$= \sqrt{l^{2} + b^{2} + h^{2}} = \sqrt{8^{2} + 6^{2} + 5^{2}} cm = \sqrt{64 + 36 + 25} cm = \sqrt{125} cm = 11.2 cm$

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What is the maximum length of a pencil that can be placed in a rectangular box of dimensions (8 cm × 6 cm × 5 cm)? (a) 8 cm (b) 9.5 cm (c) 19 cm (d) 11.2 cm

(d) 11.2 cm Maximum length of the pencil = diagonal of the box =l2+b2+h2 =82+62+52 cm=64+36+25 cm=125 cm=11.2 cm

What is the maximum length of a pencil that can be placed in a rectangular box of dimensions (8 cm × 6 cm × 5 cm)?
(a) 8 cm
(b) 9.5 cm
(c) 19 cm
(d) 11.2 cm

(d) 11.2 cm
Maximum length of the pencil = diagonal of the box
$= \sqrt{l^{2} + b^{2} + h^{2}} = \sqrt{8^{2} + 6^{2} + 5^{2}} cm = \sqrt{64 + 36 + 25} cm = \sqrt{125} cm = 11.2 cm$