Question

What is the maximum number of electrons, present in an orbit whose angular momentum is $\frac{2h}{\pi }$?

• A. 18
• B. 2
• C. 32
• D. 8

Answer 1

The correct option is C 32

Angular momentum$=\frac{nh}{2\pi }=\frac{2h}{\pi }\Rightarrow n=4$

Mass number of electrons$=2n^2$

$=2{\left(4\right)}^2=2\times 16$

$=32$