Question

What is the maximum number of emission lines obtained when the excited electron of a H atom in n= 5 drops to the ground state?

• A. 12
• B. 15
• C. 21
• D. 10

Answer 1

The correct option is D 10

Maximum number of emission lines from $n^{th}$ energy state to ground state is given by:

$=\frac{n(n-1)}{2}=\frac{5(5-1)}{2}=\frac{20}{2}=10$ lines.

option D