Question

What is the maximum number of emission lines when the excited electron of a hydrogen atom in n = 6 drops to ground state?

• A. 6
• B. 15
• C. 30
• D. 10

Answer 1

Answer: (B)

15

Maximum number of emission lines from $n^{th}$ energy state to ground state is given by:

$=\frac{n(n-1)}{2}=\frac{6(6-1)}{2}=\frac{30}{2}=15$ lines.

So, the correct option is $B$