What is the maximum number of orbitals that can be identified with the following quantum numbers?
[ $n = 3; l = 1; m_{l} = 0$ ]

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Solution

The correct option is A 1
The value of n=3 and l=1 suggests that it is a 3p orbital while the value of $m_{1}$ =0 ( magnetic quantum number) shows that the given 3p orbital is $3 p_{z}$ in nature.

Hence, the maximum number of orbitals identified by the given quantum number is only 1 i.e. $3 p_{z}$ .

Hence option 'A' is the correct answer.

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Similar questions

What is the maximum number of orbitals that can be identified with the following quantum numbers?

$n = 3, l = + 1, m_{l} = 0$

n = 2, l = 1, m_{l} = 0

n = 3, l = 1

m = + 1

n = 3, l = 1

m = - 1

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