What is the maximum sum of the terms in the arithmetic progression 25, 24, 23, 22.......?

325

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345

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332.5

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350

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Solution

The correct option is A 325
The maximum sum would occur when we take the sum of all the positive terms of the series. The series 25, 24, 23,... 1, 0 has 26 terms. The sum of the series would be given by:
$n \times a v e r a g e = 26 \times 12.5 = 325$
Option (a) is correct.

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