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Question

What Is the maximum value of sin3θcos2θ+cos3θsin2θ ?

A
I
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B
2
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C
4
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D
10
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Solution

The correct option is B I
We know that sin(A+B)=sinAcosB+sinBcosA
Substituting A=3θ and B=2θ we get,
sin(2θ+3θ)=sin2θCos3θ+sin3θCos2θ

sin5θ=sin2θCos3θ+sin3θCos2θ
Maximum value of sin5θ is 1.

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