What is the maximum wavelength of line of Balmer series of hydrogen spectrum? (R=1.09×107m−1)
A
400 nm
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B
660 nm
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C
486 nm
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D
434 nm
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Solution
The correct option is B 660 nm 1λ=RH×Z2(1n21−1n22)
For maximum wavelength in the Balmer series n2=3;n1=2 1λ=1.09×107×12(122−132) 1λ=1.09×107(14−19) λ=6.60×10−7m=660nm