What is the mean proportional between the number $0.32$ and $0.02$ ?

0.08

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0.04

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0.06

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0.64

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Solution

The correct option is A $0.08$
The mean proportional $= \sqrt{0.32 \times 0.02}$
$= \sqrt{0.0064}$
$= 0.08$ .

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Question 5 (i)
A study was conducted to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days isas follows:
$\begin{matrix} 0.03 & 0.08 & 0.08 & 0.09 & 0.04 & 0.17 0.16 & 0.05 & 0.02 & 0.06 & 0.18 & 0.20 0.11 & 0.08 & 0.12 & 0.13 & 0.22 & 0.07 0.08 & 0.01 & 0.10 & 0.06 & 0.09 & 0.18 0.11 & 0.07 & 0.05 & 0.07 & 0.01 & 0.04 \end{matrix}$
(i) Make a grouped frequency distribution table for this data with class intervals as 0.00 - 0.04, 0.04 - 0.08, and so on.

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What is the mean proportional between the number 0.32 and 0.02?

The correct option is A 0.08The mean proportional=√0.32×0.02 =√0.0064=0.08.

What is the mean proportional between the number $0.32$ and $0.02$ ?

The correct option is A $0.08$
The mean proportional $= \sqrt{0.32 \times 0.02}$
$= \sqrt{0.0064}$
$= 0.08$ .