Question

what is the measure of an angle whose complement is twice its measure?

Answer 1

Dear Student,
$$\begin{gathered} lettheangle=x \\ thenthecomplemetwillbe=(90-x) \\ given,x=2\left(90-x\right) \\ x=180-2x \\ x+2x=180 \\ 3x=180 \\ x=\frac{180}{3} \\ x=60 \\ Henc\mathit{e}\mathbf{,}\mathbf{}\mathit{t}\mathit{h}\mathit{e}\mathbf{}\mathit{a}\mathit{n}\mathit{g}\mathit{l}\mathit{e}\mathbf{}\mathit{i}\mathit{s}\mathbf{}\mathbf{60}\mathbf{°} \end{gathered}$$
Regards