What is the median for the following data?
shoe size
$2$
$3$
$4$
$5$
$6$
frequency
$10$
$20$
$12$
$14$
$11$

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4$

Shoe Size

Frequency

Position(cf)

$2$

$10$

$10$

$3$

$20$

$30$

$4$

$12$

$42$

$5$

$14$

$56$

$6$

$11$

$67$

Sum of frequency $= 10 + 20 + 12 + 147 + 11 = 67 (o d d)$
Median is at $(\frac{n + 1}{2}) = (\frac{67 + 1}{2}) = \frac{68}{2} = 34$
$3 r d$ posotion comes after $30 t h$ but before $42$
$M e d i a n = 4$

Suggest Corrections

$x$	$2 - 4$	$4 - 6$	$6 - 8$	$8 - 10$	$10 - 12$
frequency	$1$	$3$	$2$	$4$	$10$

$X$	$0 - 5$	$5 - 10$	$10 - 15$	$15 - 20$	$20 - 25$
frequency	$2$	$4$	$6$	$8$	$10$

Farm size	$2 - 5$	$5 - 8$	$8 - 11$	$11 - 14$	$14 - 17$
Rooms	$4$	$8$	$12$	$16$	$20$

Size	$2$	$3$	$4$	$5$	$6$	$7$	$8$
Frequency	$10$	$12$	$25$	$20$	$25$	$15$	$11$

Scores	$2$	$4$	$6$	$8$	$10$	$12$	$14$	$16$
Frequency	$4$	$2$	$3$	$4$	$5$	$6$	$5$	$4$