Question

What is the median of $10,14,86,2,6,8,99,1$.

Answer 1

To find the median we must first arrange the set of given numbers in increasing order.

The increasing order is as follows-

1,2,6,8,10,14,86,99

When the number of terms are even the median is the average of the $(\frac{n}{2}{)}^{th}$ term

and $(\frac{n+2}{2}{)}^{th}$ term

$(\frac{n}{2}{)}^{th}term=(\frac{8}{2}{)}^{th}term=8$

$(\frac{n+2}{2}{)}^{th}term=(\frac{8+2}{2}{)}^{th}=(\frac{10}{2}{)}^{th}term=10$

$Median=\frac{8+10}{2}=9$