Question

What is the median of the first $10$ natural number?

Answer 1

Determine the median of the first $10$ natural number.

The median is the number in the middle of a list of numbers in ascending order, from lowest to highest.

The median is the middlemost element if the total number of elements in the list is odd, and the median is the average of the middlemost two values if the total number of elements in the list is even.

Median $=\frac{\left(\frac{n}{2}\right)th+\left(\frac{n}{2}+1\right)th}{2},n-even$

List of first $10$ natural numbers are: $1,2,3,4,5,6,7,8,9,10$.

Here is the total number of elements in the list is even.

And the two middlemost elements are $5,6$

The required median is:

$\begin{array}{rcl}\mathrm{Median}& =& \frac{5+6}{2}\\ & \Rightarrow & \mathrm{Median}=\frac{11}{2}\\ & \Rightarrow & \mathrm{Median}=5.5\end{array}$

Hence, the required median of the first ten natural numbers$=5.5$.