What is the melting point of benzene if - H fusion -9-95 kJ - mol and - S fusion -35-7 J - K - mol- A- 278-70 CB- 278-7 KC- 300 KD- 298 K

The correct option is B 278.7 K Δ S = Δ H/T T = Δ H/Δ S = 9950/35.7 = 278.7K ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Phase Change

What is the m...

Question

What is the melting point of benzene if $Δ H_{f u s i o n} = 9.95 k J / m o l$ and $Δ S_{f u s i o n} = 35.7 J / K - m o l$ ?

278.7⁰C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

278.7 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

300 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

298 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Δ H_{f u s i o n} = 9.95 k J / m o l

S_{f u s i o n} = 35.7

Δ S

X (s) at 100 K ⟶ X (l) at 200 K

X_{(s)} = 100 K; Δ H_{f u s i o n} = 20 k J / m o l; C_{p, m} (X, l) = 10 J / m o l . K

m o l^{- 1}

K^{- 1} m o l^{- 1}

30 g

154 g m o l^{- 1}

250 g

2.61 K k g m o l^{- 1}

{80.1}^{o} C .

{m o l}^{- 1}

K_{f}

{m o l}^{- 1}

Join BYJU'S Learning Program