What is the melting point of benzene if - Hfusion-9-95 kJ-mol and Sfusion-35-7 J-Kmol -

The correct option is C 278 K Δ S_fusion=Δ H_fusionT #160; #160; T=Δ HΔ S=9.95 × 100035.7=278 K ...

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Question

What is the melting point of benzene if $Δ H_{f u s i o n} = 9.95 k J / m o l$ and $S_{f u s i o n} = 35.7$ J/Kmol ?

270 K

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278 K

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300 K

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298 K

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Solution

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Δ H_{f u s i o n} = 9.95 k J / m o l

Δ S_{f u s i o n} = 35.7 J / K - m o l

Δ S

X (s) at 100 K ⟶ X (l) at 200 K

X_{(s)} = 100 K; Δ H_{f u s i o n} = 20 k J / m o l; C_{p, m} (X, l) = 10 J / m o l . K

(Δ H - Δ U)

(C O)

300 K

R = \frac{25}{3} J/Kmol

m o l^{- 1}

K^{- 1} m o l^{- 1}

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