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Question

What is the minimum distance between two Na+ ions which are present along the edges in an ideal NaCl type crystal? Let, rNa+= radius of Na + and rCl−= radius of Cl−.

A

2(rNa+)
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B
2×(2+1)rNa+
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C
2rCl
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D
2×(rNa++rCl)
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Solution

The correct option is D 2×(rNa++rCl)
  • One face of NaCl crystal lattice looks like,
  • Na+ ions are situated at the centre of every edge in octahedral voids.
  • The minimum distance between two Na+ ions is AC
(AC)2=(AB)2+(BC)2
d=2(rCl+rNa+)
The minimum distance between two Na+ ions which are present along the edges is 2×(rNa++rCl).



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