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Characteristics of Chemical Equilibrium

What is the m...

Question

What is the minimum mass of CaCO $_{3} (s)$ required to establish equilibrium in a $6.5$ litres container for the following reaction $(K_{c} = 0.05 {molL}^{- 1})$ ?
$C a C O_{3} (s) ⇌ C a O (s) + C O_{2} (g)$

32.5

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24.6

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40.9

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8.0

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Solution

The correct option is A $32.5$ g
$K_{c} = [C O_{2}] = 0.05$ mol/litre

So, moles of $C O_{2} = 6.50 \times 0.05$ moles $= 0.3250$ moles
$C a C O_{3} ⇌ C a O + C O_{2}$

1 mole of $C O_{2} = 1$ mole of CaCO $_{3}$

$0.3250$ moles of $C O_{2} = 0.3250$ moles of $C a C O_{3} = 0.3250 \times 100$ g of $C a C O_{3} = 32.5$ g of $C a C O_{3}$

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