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Abnormal Colligative Properties

What is the m...

Question

What is the minimum mass of CaCO₃(s) below which it decomposes completely, required to establish equilibrium in a 6.50 lit container.

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Solution

CaCO3(s) <----> CaO(s) + CO2(g)

I solved this problem by setting Kc=[CO2].

That means, CO2=0.050M
0.050mol/L x 6.50L = 0.325 mol CO2

I then used stoichiometry to find mass of CaCO3.
answer (32.53g)

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