What is the minimum number of eggs required to support a plan weighing 1.8 N? Each egg can tolerate 0.5 N.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
In the above situations, the weight of the board will be distributed on the eggs equally.
The maximum weight, one egg can hold is $0.5 N$ .

Weight per egg:
For plank A, $W_{A} = \frac{1.8}{2} = 0.9 N$
For plank B, $W_{B} = \frac{1.8}{3} = 0.6 N$
For plank C, $W_{C} = \frac{1.8}{4} = 0.45 N$
For plank D, $W_{D} = \frac{1.8}{5} = 0.36 N$

Plank C and D can support the plank without breaking because in these cases the weight per egg is less than $0.5 N$ . Hence, a minimum of 4 eggs is required to support the board.

Suggest Corrections

Similar questions

2^{3}

2013		₹
April 1	Started business with	45,000
May 10	Withdrew from business for personal use	10,000
July 15	Further Capital introduced	55,000
Nov. 30	Income tax paid	5,000
2014
Mar. 31	Profit for the year	30,000

Identify the missing label in the following image.

(2^{1})^{2}

C o n s i d e r t h e f o l l o w i n g s t a t e m e n t s :

F_{00} (0) - 1, F_{00} (1) = 1

F_{00} (n) = 10 \times F_{00} (n - 1) + 100 \times F_{00} (n - 2) f o r n \geq 2

T h e n w h a t w i l l b e t h e v a l u e o f F_{00} (3) ?

Join BYJU'S Learning Program