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Common Ion Effect

What is the m...

Question

What is the minimum pH of a solution $0.10 M$ in ${M g}^{2 +}$ from which $M g {(O H)}_{2}$ will not precipitate? $K_{s p} M g {(O H)}_{2} = 1.2 \times 10^{- 11} M^{3}$

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Solution

Given that,
$K_{s p} M g {(O H)}_{2} = [{M g}^{2 +}] {[{O H}^{-}]}^{2}$
$1.2 \times 10^{- 11} = [0.1] {[{O H}^{-}]}^{2}$
${[{O H}^{-}]}^{2} = 1.2 \times 10^{- 10}$
$[{O H}^{-}] = 1.0954 \times 10^{- 5} M$
$p O H = - {log}_{10} (1.0954) = 4.96$
$p H = 14 - 4.96 = 9.04$

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