What is the minimum size of $R O M$ required to store the complete truth table of an 8-bit $\times$ 8-bit multiplier?

64 K \times 16

bits

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32 K \times 16

bits

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16 K \times 32

bits

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64 K \times 32

bits

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Solution

The correct option is A $64 K \times 16$ bits
$M u l t i p l y i n g t w o 8 - b i t n u m b e r s w i l l g i v e$
$r e s u l t i n m a x i m u m 16 b i t s .$

$T o t a l n u m b e r o f m u l t i p l i c a t i o n s p o s s i b l e$
$2^{8} \times 2^{8} = 64 K$

$H e n c e s p a c e r e q u i r e d = 64 K \times 16 b i t s .$

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