CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Law of Conservation of Mechanical Energy

What is the m...

Question

What is the minimum volume of a block of wood (density $= 850 k g / m^{3})$ if it is to hold a 50 kg woman entirely above the water when she stands on it ?

Open in App

Solution

Weight of both(block+woman)=upthrust on 100% volume of block
$∴$ $50 + V \times (850) = V \times (1000)$
$∴$ $V = 0.33$ m $^{3}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A woman of mass

50 k g

stands on a wooden block placed over a tank of water. The wooden block is such that the woman is entirely above water. If relative density of wood is

0.85,

the volume of the wooden block is:

Q. A block of wood has mass 200 kg. If the density of wood is 800

k g / m^{3}

, its volume will be:

Q. A block of wood of mass

24

kg floats on water. The volume of wood is

0.032

m^{3}

. Find the volume of block below the surface of water. (Density of water

= 1000

m^{- 3}

Q. A block of wood of mass

24

kg floats on water. The volume of wood is

0.032

m^{3}

. Find the density of wood.(Density of water

= 1000

m^{- 3}

Q. A block of wood floats in water

(4 / 5) t h

of its volume submerged. If the same block just floats in a liquid, the density of liquid in

{kg/m}^{3}

is
(Take density of water as

1000 {kg/m}^{3}

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

The Law of Conservation of Mechanical Energy

PHYSICS

Watch in App

explore_more_icon

Explore more

Law of Conservation of Mechanical Energy

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon