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Standard XII

Chemistry

Van't Hoff Factor

What is the m...

Question

What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298 K? (For calcium sulphate, K_sp is 9.1 × 10^–6).

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Solution

Let the solubility of CaSO₄ be s.

Molecular mass of CaSO₄ = 136 g/mol

Solubility of in gram/L = 3.02 × 10^–3 × 136

= 0.41 g/L

This means that we need 1L of water to dissolve 0.41g of CaSO₄

Therefore, to dissolve 1g of CaSO₄ we require of water.

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Similar questions

Q. Hard water required for an experiment is not available in a school laboratory. However, the following salts are available in the laboratory. Select the salts which may be dissolved in water to make it hard for the experiment :

(1) calcium sulphate
(2) sodium sulphate
(3) calcium chloride
(4) potassium sulphate
(5) sodium hydrogen carbonate
(6) magnesium chloride

Hard water required for an experiment is not available in a school laboratory. However, following salts are available in the laboratory. Select the salts which may be dissolved in water to make it hard for the experiment

(1) Calcium Sulphate

(2) Sodium Sulphate

(3) Calcium Chloride

(4) Potassium Sulphate

(5) Sodium Hydrogen Carbonate

(6) Magnesium Chloride

Q. A mixture of

100 m m o l

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and

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100 m L

. The mass of calcium sulphate formed and the concentration of

O H^{-}

in resulting solution, respectively, are:

[Molar mass of

C a (O H)_{2}, N a_{2} S O_{4}

and

C a S O_{4}

are

74, 143

and

136 g m o l^{- 1}

, respectively;

K_{s p}

C a (O H)_{2}

5.5 \times 10^{- 6}]

Q. A sample of hard water contains

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Q. A student requires hard water for an experiment in his laboratory which is not available in the neighbouring area. In the laboratory there are some salts, which when dissolved in distilled water can convert it into hard water. Select from the following groups of salts, which when dissolved in distilled water will make it hard.
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What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298 K? (For calcium sulphate, Ksp is 9.1 × 10–6).

Let the solubility of CaSO4 be s. Molecular mass of CaSO4 = 136 g/mol Solubility of in gram/L = 3.02 × 10–3 × 136 = 0.41 g/L This means that we need 1L of water to dissolve 0.41g of CaSO4 Therefore, to dissolve 1g of CaSO4 we require of water.

What is the minimum volume of water required to dissolve 1g of calcium sulphate at 298 K? (For calcium sulphate, K_sp is 9.1 × 10^–6).

Let the solubility of CaSO₄ be s.

Molecular mass of CaSO₄ = 136 g/mol

Solubility of in gram/L = 3.02 × 10^–3 × 136

= 0.41 g/L

This means that we need 1L of water to dissolve 0.41g of CaSO₄

Therefore, to dissolve 1g of CaSO₄ we require of water.