What is the missing digit which makes the number 128_2 exactly divisible by 8?
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is D3 We know the divisibility rule for 8: If the last three digits are divisible by 8 or last three digits of the given number are zeros, then the number is divisible by 8. Here 12832 is divisible by 8, because the last three digits is divisible by 8.