What is the molality of an aqueous solution of ethyl alcohol ( $C H_{3} C H_{2} O H$ , molar mass = 46.0 g mol $^{- 1}$ ) which contains 50.0 g of alcohol in 500 mL of the solution?

2.18 mol 1

^{- 1}

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3.18 mol 1

^{- 1}

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4.18 mol 1

^{- 1}

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1.18 mol 1

^{- 1}

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Solution

The correct option is A 2.18 mol 1 $^{- 1}$
given that $50 g$ alcohol
Volume $= 500 m l$
morality $= \frac{N o . o f m o l e s}{v o l u m e (m l)} \times 1000$
$= \frac{50}{46 \times 500} \times 100$
$= 2.18 m o l l i t^{- 1}$

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