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Osmotic Pressure

What is the m...

Question

What is the molality of aqueous solution of urea having mole fraction of solute 0.03?

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Solution

1. Molarity of water = 55.5 M

55.5 moles is present in 1 L of water.

2. So,

$χ_{u r e a} = \frac{n_{u r e a}}{n_{u r e a} + n_{w a t e r}} 0.03 = \frac{n_{u r e a}}{n_{u r e a} + 55.5} n_{u r e a} = 1.71$

3. Molality = $\frac{n_{u r e a}}{M a s s o f s o l v e n t i n k g} = \frac{1.71}{1 k g} = 1.71 m o l a l$

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