What is the molarity if a $500 m L$ solution contains $20 g$ of $C a {B r}_{2}$ ?

0.1 M

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0.2 M

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0.5 M

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1 M

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5 M

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Solution

The correct option is B $0.2 M$
Calcium bromide has a molar mass of 200 g/mol.

The number of moles of $C a B r_{2} = \frac{20 g}{200 g / m o l} = 0.10 m o l$

Volume of solution $= 500 m L \times \frac{1 L}{1000 m L} = 0.500 L$

The molarity of $C a B r_{2} = \frac{0.10 m o l}{0.500 L} = 0.2 M$

Hence the correct option is B.

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