What is the molarity if a 500 mL solution contains 20 g of $C a B r_{2}$ ?

0.1 M

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0.2 M

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0.5 M

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1 M

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5 M

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Solution

The correct option is A 0.2 M
Molar mass of the solute $C a B r_{2} = 40 + (2 \times 80) = 200 g / m o l e$
Number of moles of solute = $\frac{20}{200} = 0.1$ moles
volume $=$ $500 m L$ $=$ $0.5 L$

So, Molarity $= \frac{n u m b e r o f m o l e s}{v o l u m e} \times 1000 = \frac{0.1}{500} \times 1000 = 0.2 M$

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