What is the molarity of $0.1 m o l e s$ of $N a C l$ dissolved in a solution which has a total volume of $500 m L$ ?

2 \times 10^{- 4} M

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50 M

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0.2 M

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0.05 M

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Solution

The correct option is B $0.2 M$
Molarity of NaCl $= \frac{No. of moles of NaCl}{Volume of solution (Litres)} = \frac{0.1 m o l e s}{500 m L / 1000} = \frac{0.1}{0.5} = 0.2 M$
Molarity of NaCl $= 0.2 M$

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