What is the molarity of $0.2 m o l e s$ of iron (III) chloride dissolved in $0.5 L$ of the solution?

0.2 M

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0.4 M

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0.1 M

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0.5 M

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Solution

The correct option is A $0.4 M$
Molarity of Solution $= \frac{No. of moles}{Volume of solution (L)}$

$= \frac{0.2 m o l e s}{0.5 L i t r e s}$

$= 0.4 M o l a r$

$= 0.4 M$

Therefore, the option is B.

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