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Thermodynamic Processes

What is the m...

Question

What is the molarity of $11.2 V$ of $H_{2} O_{2}$ ?

1

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2

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5.6

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11.2

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Solution

The correct option is B $1$
$1$ L of $H_{2} O_{2}$ provides $11.2$ L of $O_{2}$ at STP.
Moles of $O_{2}$ = $\frac{11.2}{22.4} = 0.5$
$n_{H_{2} O_{2}}$ required = 0.5 x 2.
$M_{H_{2} O_{2}} = \frac{n_{H_{2} O_{2}}}{V_{s o l u t i o n}} = 1 M$

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