What is the molarity of a solution containing $10 g$ of $N a O H$ in $500 m L$ of the solution?

0.25 m o l

L^{- 1}

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0.75 m o l

L^{- 1}

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0.5 m o l

L^{- 1}

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1.25 m o l

L^{- 1}

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Solution

The correct option is C $0.5 m o l$ $L^{- 1}$
Molarity = $\frac{n \times 1000}{V_{m l}}$

Molar mass of $N a O H$ = $40 g / m o l$

No of moles of $N a O H$ = $\frac{10}{40} = 0.25 m o l$

therefore Molarity = $\frac{0.25 \times 1000}{500} = \frac{250}{500} = 0.5 m o l L^{- 1}$

Hence, the correct option is $C$

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