What is the molarity of an N aOH solution if 250 mL contains 1 mg of N aOH -A- 10-1 MB- 10-2 MC- 10-4 MD- 10-3 M

The correct option is C 10^−4 MNumber of moles of NaOH = given mass of NaOHmolar mass = nbsp;10^ 340 Molarity = number of moles of solutevolume of solut ...

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Standard XII

Chemistry

Molarity

What is the m...

Question

What is the molarity of an $N a O H$ solution if 250 mL contains 1 mg of $N a O H$ ?

10^{- 1} M

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10^{- 2} M

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10^{- 4} M

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10^{- 3} M

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Solution

Step 1:
$Number of moles of N a O H = \frac{given mass of N a O H}{molar mass} = \frac{10^{- 3}}{40}$
Step 2:

$Molarity = \frac{number of moles of solute}{volume of solution in mL} \times 1000$

$Molarity = \frac{\frac{10^{- 3}}{40} \times 1000}{250} = 10^{- 4} M$
Hence, option (C) is correct.

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Molarity

Standard XII Chemistry

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What is the molarity of an NaOH solution if 250 mL contains 1 mg of NaOH?

Step 1: Number of moles of NaOH=given mass of NaOHmolar mass=10−340Step 2: Molarity=number of moles of solutevolume of solution in mL×1000 Molarity=10−340×1000250=10−4 MHence, option (C) is correct.

What is the molarity of an $N a O H$ solution if 250 mL contains 1 mg of $N a O H$ ?

Step 1:
$Number of moles of N a O H = \frac{given mass of N a O H}{molar mass} = \frac{10^{- 3}}{40}$
Step 2:

$Molarity = \frac{number of moles of solute}{volume of solution in mL} \times 1000$

$Molarity = \frac{\frac{10^{- 3}}{40} \times 1000}{250} = 10^{- 4} M$
Hence, option (C) is correct.