Question

What is the molarity of $H_{2}S{O}_4$ solution, that has a density $1.84gm/cc$ at ${35}^{\circ }C$ and contains solute $98\%$ by weight?

• A. $4.18M$
• B. $8.14M$
• C. $18.4M$
• D. $18M$

Answer 1

Answer: (C)

$18.4M$

Molarity=$\frac{wtofsolute}{mol.wt}\times \frac{1000}{vol.ofsolution\left(inmL\right)}$

Volume of solution$=\frac{mass}{density}=\frac{100}{1.84}=54.34mL$

Now molarity$=\frac{98}{98}\times \frac{1000}{54.34}=18.4M$

Hence, the correct option is $C$