What is the moment of force developed about the hinge of a door if a person tries to open it with a force of 100 N, the force being applied normal to the door at handle which is at a distance of 60 cm from the hinge?
60 Nm
We know that moment of a force about an axis is given by,
Moment of Force = Force × Perpendicular distance
As force is being applied normally, perpendicular distance, d = 60 cm = 0.6 m
T = F × d = 100 N × 0.6 m = 60 Nm