What is the momentum of photon of energy 3 MeV in $k g m s^{- 1}$ ?

9 \times 10^{- 21}

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1.6 \times 10^{- 21}

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3 \times 10^{- 28}

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9 \times 10^{- 28}

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Solution

The correct option is B $1.6 \times 10^{- 21}$
$p = \frac{E}{C} = \frac{3 \times 10^{6} \times 1.6 \times 10^{- 19}}{3 \times 10^{8}} = 1.6 \times 10^{- 21} k g m s^{- 1}$

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