What is the natural frequency of vibration of a simple pendulum of time period 2s?

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Solution

Step-1 Given data
Time period $= 2 s$
Step-2 Finding the frequency
Frequency of vibration $= \frac{1}{T i m e p e r i o d o f o s c i l l a t i o n}$
Frequency of vibration $= \frac{1}{2}$
$= 0.5 s^{- 1} o r H z$
Final answer: Frequency = $0.5 H z$

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