Question

What is the nature of the curve $x^2-2=0$

Answer 1

The equation of the given curve is

$F(x,y)=x^2-2=0$

Here $F(-x,y)={(-x)}^2-2=x^2-2=0=F(x,y)$

$F(-x,-y)={(-x)}^2-2=x^2-2=0=F(x,y)$

$\therefore$ the given curve is symmetrical about the $x-$axis,$y-$axis and about the origin.