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Question

What is the nature of the graph : y=āˆ’4x2+6

A
parabola not passing through origin
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B
Hyperbola not passing through origin
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C
Ellipse not passing through origin
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D
it is not a conic
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Solution

The correct option is D parabola not passing through origin
y=4x2+6
y6=4x2
x2=(y6)4
X2=4aY
Where a=116 and Y=y6.
Hence the above equation is of a parabola not passing through origin.

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